백준 1929번 파이썬 (소수) n,m=map(int, input().split()) a=[1]*(m+1) a[0]=0 a[1]=0 for i in range(2,m+1): for j in range(2,m//i+1): if a[i]==1: a[i*j]=0 for k in range(1,m+1): if a[k]==1 and k>=n: print(k) 백준 풀이 2022.08.27